Matematika Sekolah Menengah Atas 100(0) × 45^0 + ⁶log 36 - √64 + 1³ × 4! = ..
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100(0) × 45^0 + ⁶log 36 - √64 + 1³ × 4! = ..
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Penjelasan dengan langkah-langkah:

100(0) × 45⁰ + ⁶log 36 - √64 + 1³ × 4!

= (100(0) × 45⁰) + ⁶log 36 - √64 + 1³ × 4!

= (0 × 1) + ⁶log 6² - √8² + [(1 × 1 × 1) × (4 × 3 × 2 × 1)]

= 0 + 2 - 8 + [1 × 24]

= 0 + 2 - 8 + 24

= 2 - 8 + 24

= -6 + 24

= 24 - 6

= 18

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Jawaban:

18

Penjelasan dengan langkah-langkah:

100(0) × 45^0 + ⁶log 36 - √64 + 1³ × 4!

= (100(0) × 45^0) + ⁶log 36 - √64 + (1³ × 4!)

= (100×0 × 45^0) + ⁶log6² - √8² + ((1×1×1) × (4×3×2×1))

= (0 × 1) + 2 - 8 + (1 × 24)

= 0 + 2 - 8 + 24

= 18

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